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2(2x+3)=-3(x-4)
We move all terms to the left:
2(2x+3)-(-3(x-4))=0
We multiply parentheses
4x-(-3(x-4))+6=0
We calculate terms in parentheses: -(-3(x-4)), so:We get rid of parentheses
-3(x-4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
4x+3x-12+6=0
We add all the numbers together, and all the variables
7x-6=0
We move all terms containing x to the left, all other terms to the right
7x=6
x=6/7
x=6/7
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