3x+x+4=21x+16-12

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Solution for 3x+x+4=21x+16-12 equation: 



3x+x+4=21x+16-12

We move all terms to the left:

3x+x+4-(21x+16-12)=0

We add all the numbers together, and all the variables

3x+x-(21x+4)+4=0

We add all the numbers together, and all the variables

4x-(21x+4)+4=0

We get rid of parentheses

4x-21x-4+4=0

We add all the numbers together, and all the variables

-17x=0

x=0/-17

x=0

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