15(2x+2)=(3x+5)

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Solution for 15(2x+2)=(3x+5) equation: 



15(2x+2)=(3x+5)

We move all terms to the left:

15(2x+2)-((3x+5))=0

We multiply parentheses

30x-((3x+5))+30=0



We calculate terms in parentheses: -((3x+5)), so:

(3x+5)

We get rid of parentheses

3x+5

Back to the equation:

-(3x+5)



We get rid of parentheses

30x-3x-5+30=0

We add all the numbers together, and all the variables

27x+25=0

We move all terms containing x to the left, all other terms to the right

27x=-25

x=-25/27

x=-25/27

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