3x+8+4x=-8(x-6)-8(13x-+5)

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Solution for 3x+8+4x=-8(x-6)-8(13x-+5) equation: 



3x+8+4x=-8(x-6)-8(13x-+5)

We move all terms to the left:

3x+8+4x-(-8(x-6)-8(13x-+5))=0

We add all the numbers together, and all the variables

3x+4x-(-8(x-6)-8(+13x))+8=0

We add all the numbers together, and all the variables

7x-(-8(x-6)-8(+13x))+8=0



We calculate terms in parentheses: -(-8(x-6)-8(+13x)), so:

-8(x-6)-8(+13x)

We multiply parentheses

-8x-104x+48

We add all the numbers together, and all the variables

-112x+48

Back to the equation:

-(-112x+48)



We get rid of parentheses

7x+112x-48+8=0

We add all the numbers together, and all the variables

119x-40=0

We move all terms containing x to the left, all other terms to the right

119x=40

x=40/119

x=40/119

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