3x+5x+7-4x=19+1x

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Solution for 3x+5x+7-4x=19+1x equation: 



3x+5x+7-4x=19+1x

We move all terms to the left:

3x+5x+7-4x-(19+1x)=0

We add all the numbers together, and all the variables

3x+5x-4x-(x+19)+7=0

We add all the numbers together, and all the variables

4x-(x+19)+7=0

We get rid of parentheses

4x-x-19+7=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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