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3X^2+27X+7=0
a = 3; b = 27; c = +7;
Δ = b2-4ac
Δ = 272-4·3·7
Δ = 645
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-\sqrt{645}}{2*3}=\frac{-27-\sqrt{645}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+\sqrt{645}}{2*3}=\frac{-27+\sqrt{645}}{6} $
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