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3x+5=4x^2
We move all terms to the left:
3x+5-(4x^2)=0
determiningTheFunctionDomain -4x^2+3x+5=0
a = -4; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-4)·5
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*-4}=\frac{-3-\sqrt{89}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*-4}=\frac{-3+\sqrt{89}}{-8} $
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