-36=4(2a-5)6a

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Solution for -36=4(2a-5)6a equation:



-36=4(2a-5)6a
We move all terms to the left:
-36-(4(2a-5)6a)=0
We calculate terms in parentheses: -(4(2a-5)6a), so:
4(2a-5)6a
We multiply parentheses
48a^2-120a
Back to the equation:
-(48a^2-120a)
We get rid of parentheses
-48a^2+120a-36=0
a = -48; b = 120; c = -36;
Δ = b2-4ac
Δ = 1202-4·(-48)·(-36)
Δ = 7488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{7488}=\sqrt{576*13}=\sqrt{576}*\sqrt{13}=24\sqrt{13}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-24\sqrt{13}}{2*-48}=\frac{-120-24\sqrt{13}}{-96} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+24\sqrt{13}}{2*-48}=\frac{-120+24\sqrt{13}}{-96} $

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