3x+4x+8=3(x-2)

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Solution for 3x+4x+8=3(x-2) equation: 



3x+4x+8=3(x-2)

We move all terms to the left:

3x+4x+8-(3(x-2))=0

We add all the numbers together, and all the variables

7x-(3(x-2))+8=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

7x-3x+6+8=0

We add all the numbers together, and all the variables

4x+14=0

We move all terms containing x to the left, all other terms to the right

4x=-14

x=-14/4

x=-3+1/2

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