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-1/3x*2-2/3x+1/9=0
Domain of the equation: 3x*2!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
36x^2/486x^2+(-243x)/486x^2+(-216x)/486x^2=0
We multiply all the terms by the denominator
36x^2+(-243x)+(-216x)=0
We get rid of parentheses
36x^2-243x-216x=0
We add all the numbers together, and all the variables
36x^2-459x=0
a = 36; b = -459; c = 0;
Δ = b2-4ac
Δ = -4592-4·36·0
Δ = 210681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{210681}=459$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-459)-459}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-459)+459}{2*36}=\frac{918}{72} =12+3/4 $
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