3x+4=3(x+2)-2x-4

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Solution for 3x+4=3(x+2)-2x-4 equation: 



3x+4=3(x+2)-2x-4

We move all terms to the left:

3x+4-(3(x+2)-2x-4)=0



We calculate terms in parentheses: -(3(x+2)-2x-4), so:

3(x+2)-2x-4

We add all the numbers together, and all the variables

-2x+3(x+2)-4

We multiply parentheses

-2x+3x+6-4

We add all the numbers together, and all the variables

x+2

Back to the equation:

-(x+2)



We get rid of parentheses

3x-x-2+4=0

We add all the numbers together, and all the variables

2x+2=0

We move all terms containing x to the left, all other terms to the right

2x=-2

x=-2/2

x=-1

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