4(y+10)+y=2(y+2)+4

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Solution for 4(y+10)+y=2(y+2)+4 equation: 



4(y+10)+y=2(y+2)+4

We move all terms to the left:

4(y+10)+y-(2(y+2)+4)=0

We add all the numbers together, and all the variables

y+4(y+10)-(2(y+2)+4)=0

We multiply parentheses

y+4y-(2(y+2)+4)+40=0



We calculate terms in parentheses: -(2(y+2)+4), so:

2(y+2)+4

We multiply parentheses

2y+4+4

We add all the numbers together, and all the variables

2y+8

Back to the equation:

-(2y+8)



We add all the numbers together, and all the variables

5y-(2y+8)+40=0

We get rid of parentheses

5y-2y-8+40=0

We add all the numbers together, and all the variables

3y+32=0

We move all terms containing y to the left, all other terms to the right

3y=-32

y=-32/3

y=-10+2/3

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