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3x+4=-1/24x
We move all terms to the left:
3x+4-(-1/24x)=0
Domain of the equation: 24x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
3x+1/24x+4=0
We multiply all the terms by the denominator
3x*24x+4*24x+1=0
Wy multiply elements
72x^2+96x+1=0
a = 72; b = 96; c = +1;
Δ = b2-4ac
Δ = 962-4·72·1
Δ = 8928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8928}=\sqrt{144*62}=\sqrt{144}*\sqrt{62}=12\sqrt{62}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-12\sqrt{62}}{2*72}=\frac{-96-12\sqrt{62}}{144} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+12\sqrt{62}}{2*72}=\frac{-96+12\sqrt{62}}{144} $
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