2/3(3x+6)=1/2(2x-4)

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Solution for 2/3(3x+6)=1/2(2x-4) equation:



2/3(3x+6)=1/2(2x-4)
We move all terms to the left:
2/3(3x+6)-(1/2(2x-4))=0
Domain of the equation: 3(3x+6)!=0
x∈R
Domain of the equation: 2(2x-4))!=0
x∈R
We calculate fractions
(4x2/(3(3x+6)*2(2x-4)))+(-3x3/(3(3x+6)*2(2x-4)))=0
We calculate terms in parentheses: +(4x2/(3(3x+6)*2(2x-4))), so:
4x2/(3(3x+6)*2(2x-4))
We multiply all the terms by the denominator
4x2
We add all the numbers together, and all the variables
4x^2
Back to the equation:
+(4x^2)
We calculate terms in parentheses: +(-3x3/(3(3x+6)*2(2x-4))), so:
-3x3/(3(3x+6)*2(2x-4))
We multiply all the terms by the denominator
-3x3
We add all the numbers together, and all the variables
-3x^3
We do not support expression: x^3

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