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3x+4/2=1+(4x/3)
We move all terms to the left:
3x+4/2-(1+(4x/3))=0
We add all the numbers together, and all the variables
3x-(1+(+4x/3))+4/2=0
We add all the numbers together, and all the variables
3x-(1+(+4x/3))+2=0
We multiply all the terms by the denominator
3x*3))-(1+(+4x+2*3))=0
We add all the numbers together, and all the variables
3x*3))-(1+(4x+6))=0
We add all the numbers together, and all the variables
3x*3))-(1+(4x=0
Wy multiply elements
9x^2=0
a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{18}=0$
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