3c+6=3(2+c)

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Solution for 3c+6=3(2+c) equation: 



3c+6=3(2+c)

We move all terms to the left:

3c+6-(3(2+c))=0

We add all the numbers together, and all the variables

3c-(3(c+2))+6=0



We calculate terms in parentheses: -(3(c+2)), so:

3(c+2)

We multiply parentheses

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

3c-3c-6+6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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