3x+4-2(x-5)=9x+8-2x

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Solution for 3x+4-2(x-5)=9x+8-2x equation: 



3x+4-2(x-5)=9x+8-2x

We move all terms to the left:

3x+4-2(x-5)-(9x+8-2x)=0

We add all the numbers together, and all the variables

3x-2(x-5)-(7x+8)+4=0

We multiply parentheses

3x-2x-(7x+8)+10+4=0

We get rid of parentheses

3x-2x-7x-8+10+4=0

We add all the numbers together, and all the variables

-6x+6=0

We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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