6(x+1)+1=4x+2(5+x)

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Solution for 6(x+1)+1=4x+2(5+x) equation:



6(x+1)+1=4x+2(5+x)
We move all terms to the left:
6(x+1)+1-(4x+2(5+x))=0
We add all the numbers together, and all the variables
6(x+1)-(4x+2(x+5))+1=0
We multiply parentheses
6x-(4x+2(x+5))+6+1=0
We calculate terms in parentheses: -(4x+2(x+5)), so:
4x+2(x+5)
We multiply parentheses
4x+2x+10
We add all the numbers together, and all the variables
6x+10
Back to the equation:
-(6x+10)
We add all the numbers together, and all the variables
6x-(6x+10)+7=0
We get rid of parentheses
6x-6x-10+7=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation

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