3x+4(3x-5)=2(4x-10)+7x

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Solution for 3x+4(3x-5)=2(4x-10)+7x equation: 



3x+4(3x-5)=2(4x-10)+7x

We move all terms to the left:

3x+4(3x-5)-(2(4x-10)+7x)=0

We multiply parentheses

3x+12x-(2(4x-10)+7x)-20=0



We calculate terms in parentheses: -(2(4x-10)+7x), so:

2(4x-10)+7x

We add all the numbers together, and all the variables

7x+2(4x-10)

We multiply parentheses

7x+8x-20

We add all the numbers together, and all the variables

15x-20

Back to the equation:

-(15x-20)



We add all the numbers together, and all the variables

15x-(15x-20)-20=0

We get rid of parentheses

15x-15x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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