4(a+3)=12+a

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Solution for 4(a+3)=12+a equation: 



4(a+3)=12+a

We move all terms to the left:

4(a+3)-(12+a)=0

We add all the numbers together, and all the variables

4(a+3)-(a+12)=0

We multiply parentheses

4a-(a+12)+12=0

We get rid of parentheses

4a-a-12+12=0

We add all the numbers together, and all the variables

3a=0

a=0/3

a=0

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