3x+4(-3+x)=-5(2x+-6)+93x+(-3*4+x*4)=-5(2x+-6)+93x+(-12+4x)=-5(2x+-6)+9

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Solution for 3x+4(-3+x)=-5(2x+-6)+93x+(-3*4+x*4)=-5(2x+-6)+93x+(-12+4x)=-5(2x+-6)+9 equation:



3x+4(-3+x)=-5(2x+-6)+93x+(-3*4+x*4)=-5(2x+-6)+93x+(-12+4x)=-5(2x+-6)+9
We move all terms to the left:
3x+4(-3+x)-(-5(2x+-6)+93x+(-3*4+x*4))=0
We add all the numbers together, and all the variables
3x+4(x-3)-(-5(2x-6)+93x+(x*4-12))=0
We multiply parentheses
3x+4x-(-5(2x-6)+93x+(x*4-12))-12=0
We calculate terms in parentheses: -(-5(2x-6)+93x+(x*4-12)), so:
-5(2x-6)+93x+(x*4-12)
We add all the numbers together, and all the variables
93x-5(2x-6)+(x*4-12)
We multiply parentheses
93x-10x+(x*4-12)+30
We get rid of parentheses
93x-10x+x*4-12+30
We add all the numbers together, and all the variables
83x+x*4+18
Wy multiply elements
83x+4x+18
We add all the numbers together, and all the variables
87x+18
Back to the equation:
-(87x+18)
We add all the numbers together, and all the variables
7x-(87x+18)-12=0
We get rid of parentheses
7x-87x-18-12=0
We add all the numbers together, and all the variables
-80x-30=0
We move all terms containing x to the left, all other terms to the right
-80x=30
x=30/-80
x=-3/8

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