-3(t+4)+20=2

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Solution for -3(t+4)+20=2 equation: 



-3(t+4)+20=2

We move all terms to the left:

-3(t+4)+20-(2)=0

We add all the numbers together, and all the variables

-3(t+4)+18=0

We multiply parentheses

-3t-12+18=0

We add all the numbers together, and all the variables

-3t+6=0

We move all terms containing t to the left, all other terms to the right

-3t=-6

t=-6/-3

t=+2

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