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3x+3x+x-2=4(x+4)
We move all terms to the left:
3x+3x+x-2-(4(x+4))=0
We add all the numbers together, and all the variables
7x-(4(x+4))-2=0
We calculate terms in parentheses: -(4(x+4)), so:We get rid of parentheses
4(x+4)
We multiply parentheses
4x+16
Back to the equation:
-(4x+16)
7x-4x-16-2=0
We add all the numbers together, and all the variables
3x-18=0
We move all terms containing x to the left, all other terms to the right
3x=18
x=18/3
x=6
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