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89=3x(2x-1)
We move all terms to the left:
89-(3x(2x-1))=0
We calculate terms in parentheses: -(3x(2x-1)), so:We get rid of parentheses
3x(2x-1)
We multiply parentheses
6x^2-3x
Back to the equation:
-(6x^2-3x)
-6x^2+3x+89=0
a = -6; b = 3; c = +89;
Δ = b2-4ac
Δ = 32-4·(-6)·89
Δ = 2145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2145}}{2*-6}=\frac{-3-\sqrt{2145}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2145}}{2*-6}=\frac{-3+\sqrt{2145}}{-12} $
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