3x+32=4x-8+7x

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Solution for 3x+32=4x-8+7x equation: 



3x+32=4x-8+7x

We move all terms to the left:

3x+32-(4x-8+7x)=0

We add all the numbers together, and all the variables

3x-(11x-8)+32=0

We get rid of parentheses

3x-11x+8+32=0

We add all the numbers together, and all the variables

-8x+40=0

We move all terms containing x to the left, all other terms to the right

-8x=-40

x=-40/-8

x=+5

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