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9x^2+30x+25=6x+10
We move all terms to the left:
9x^2+30x+25-(6x+10)=0
We get rid of parentheses
9x^2+30x-6x-10+25=0
We add all the numbers together, and all the variables
9x^2+24x+15=0
a = 9; b = 24; c = +15;
Δ = b2-4ac
Δ = 242-4·9·15
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6}{2*9}=\frac{-30}{18} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6}{2*9}=\frac{-18}{18} =-1 $
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