3x+2=x(x+5)+3

Solution for 3x+2=x(x+5)+3 equation:

3x+2=x(x+5)+3

We move all terms to the left:

3x+2-(x(x+5)+3)=0


We calculate terms in parentheses: -(x(x+5)+3), so:

x(x+5)+3

We multiply parentheses

x^2+5x+3

Back to the equation:

-(x^2+5x+3)


We get rid of parentheses

-x^2+3x-5x-3+2=0

We add all the numbers together, and all the variables

-1x^2-2x-1=0

a = -1; b = -2; c = -1;
Δ = b2-4ac
Δ = -22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{2}{-2}=-1$