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4x(2x=30)
We move all terms to the left:
4x(2x-(30))=0
We multiply parentheses
8x^2-120x=0
a = 8; b = -120; c = 0;
Δ = b2-4ac
Δ = -1202-4·8·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-120}{2*8}=\frac{0}{16} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+120}{2*8}=\frac{240}{16} =15 $
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