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3x+2=2/3(5x)
We move all terms to the left:
3x+2-(2/3(5x))=0
Domain of the equation: 35x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+2/35x)+2=0
We get rid of parentheses
3x-2/35x+2=0
We multiply all the terms by the denominator
3x*35x+2*35x-2=0
Wy multiply elements
105x^2+70x-2=0
a = 105; b = 70; c = -2;
Δ = b2-4ac
Δ = 702-4·105·(-2)
Δ = 5740
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5740}=\sqrt{4*1435}=\sqrt{4}*\sqrt{1435}=2\sqrt{1435}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-2\sqrt{1435}}{2*105}=\frac{-70-2\sqrt{1435}}{210} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+2\sqrt{1435}}{2*105}=\frac{-70+2\sqrt{1435}}{210} $
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