F(x)=(7x-5)(7x+5)

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Solution for F(x)=(7x-5)(7x+5) equation: 



(F)=(7F-5)(7F+5)

We move all terms to the left:

(F)-((7F-5)(7F+5))=0

We use the square of the difference formula

49F^2+F+25=0

a = 49; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·49·25
Δ = -4899
Delta is less than zero, so there is no solution for the equation

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