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3x+2=1/2x-5
We move all terms to the left:
3x+2-(1/2x-5)=0
Domain of the equation: 2x-5)!=0We get rid of parentheses
x∈R
3x-1/2x+5+2=0
We multiply all the terms by the denominator
3x*2x+5*2x+2*2x-1=0
Wy multiply elements
6x^2+10x+4x-1=0
We add all the numbers together, and all the variables
6x^2+14x-1=0
a = 6; b = 14; c = -1;
Δ = b2-4ac
Δ = 142-4·6·(-1)
Δ = 220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{220}=\sqrt{4*55}=\sqrt{4}*\sqrt{55}=2\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{55}}{2*6}=\frac{-14-2\sqrt{55}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{55}}{2*6}=\frac{-14+2\sqrt{55}}{12} $
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