3x+20-2=3(x+6)

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Solution for 3x+20-2=3(x+6) equation: 



3x+20-2=3(x+6)

We move all terms to the left:

3x+20-2-(3(x+6))=0

We add all the numbers together, and all the variables

3x-(3(x+6))+18=0



We calculate terms in parentheses: -(3(x+6)), so:

3(x+6)

We multiply parentheses

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

3x-3x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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