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10x+3(4-x)=2(3x+5)
We move all terms to the left:
10x+3(4-x)-(2(3x+5))=0
We add all the numbers together, and all the variables
10x+3(-1x+4)-(2(3x+5))=0
We multiply parentheses
10x-3x-(2(3x+5))+12=0
We calculate terms in parentheses: -(2(3x+5)), so:We add all the numbers together, and all the variables
2(3x+5)
We multiply parentheses
6x+10
Back to the equation:
-(6x+10)
7x-(6x+10)+12=0
We get rid of parentheses
7x-6x-10+12=0
We add all the numbers together, and all the variables
x+2=0
We move all terms containing x to the left, all other terms to the right
x=-2
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