3x+20+4(2x+1)=122

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Solution for 3x+20+4(2x+1)=122 equation: 



3x+20+4(2x+1)=122

We move all terms to the left:

3x+20+4(2x+1)-(122)=0

We add all the numbers together, and all the variables

3x+4(2x+1)-102=0

We multiply parentheses

3x+8x+4-102=0

We add all the numbers together, and all the variables

11x-98=0

We move all terms containing x to the left, all other terms to the right

11x=98

x=98/11

x=8+10/11

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