3x+2(x-5)=16+2x

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Solution for 3x+2(x-5)=16+2x equation: 



3x+2(x-5)=16+2x

We move all terms to the left:

3x+2(x-5)-(16+2x)=0

We add all the numbers together, and all the variables

3x+2(x-5)-(2x+16)=0

We multiply parentheses

3x+2x-(2x+16)-10=0

We get rid of parentheses

3x+2x-2x-16-10=0

We add all the numbers together, and all the variables

3x-26=0

We move all terms containing x to the left, all other terms to the right

3x=26

x=26/3

x=8+2/3

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