(3x-2)/5=(8-x)/2

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Solution for (3x-2)/5=(8-x)/2 equation: 



(3x-2)/5=(8-x)/2

We move all terms to the left:

(3x-2)/5-((8-x)/2)=0

We add all the numbers together, and all the variables

(3x-2)/5-((-1x+8)/2)=0

We calculate fractions


3x/()+(-((-1x+8)*5)/()=0



We calculate terms in parentheses: +(-((-1x+8)*5)/(), so:

-((-1x+8)*5)/(

We multiply all the terms by the denominator


-((-1x+8)*5)



We calculate terms in parentheses: -((-1x+8)*5), so:

(-1x+8)*5

We multiply parentheses

-5x+40

Back to the equation:

-(-5x+40)



We get rid of parentheses

5x-40

Back to the equation:

+(5x-40)



We get rid of parentheses

3x/()+5x-40=0

We multiply all the terms by the denominator


3x+5x*()-40*()=0

We add all the numbers together, and all the variables

3x+5x*()=0

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