3x+2(x+3)=41

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Solution for 3x+2(x+3)=41 equation: 



3x+2(x+3)=41

We move all terms to the left:

3x+2(x+3)-(41)=0

We multiply parentheses

3x+2x+6-41=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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