-3(n+4)+n=2(n+6)

Solution for -3(n+4)+n=2(n+6) equation:

-3(n+4)+n=2(n+6)

We move all terms to the left:

-3(n+4)+n-(2(n+6))=0

We add all the numbers together, and all the variables

n-3(n+4)-(2(n+6))=0

We multiply parentheses

n-3n-(2(n+6))-12=0


We calculate terms in parentheses: -(2(n+6)), so:

2(n+6)

We multiply parentheses

2n+12

Back to the equation:

-(2n+12)


We add all the numbers together, and all the variables

-2n-(2n+12)-12=0

We get rid of parentheses

-2n-2n-12-12=0

We add all the numbers together, and all the variables

-4n-24=0

We move all terms containing n to the left, all other terms to the right

-4n=24

n=24/-4

n=-6