3x+2(x+2)=10-(2x+5)

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Solution for 3x+2(x+2)=10-(2x+5) equation: 



3x+2(x+2)=10-(2x+5)

We move all terms to the left:

3x+2(x+2)-(10-(2x+5))=0

We multiply parentheses

3x+2x-(10-(2x+5))+4=0



We calculate terms in parentheses: -(10-(2x+5)), so:

10-(2x+5)

determiningTheFunctionDomain
-(2x+5)+10

We get rid of parentheses

-2x-5+10

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We add all the numbers together, and all the variables

5x-(-2x+5)+4=0

We get rid of parentheses

5x+2x-5+4=0

We add all the numbers together, and all the variables

7x-1=0

We move all terms containing x to the left, all other terms to the right

7x=1

x=1/7

x=1/7

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