4(2x-1)+1=2x+2-5(1-4x)

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Solution for 4(2x-1)+1=2x+2-5(1-4x) equation: 



4(2x-1)+1=2x+2-5(1-4x)

We move all terms to the left:

4(2x-1)+1-(2x+2-5(1-4x))=0

We add all the numbers together, and all the variables

4(2x-1)-(2x+2-5(-4x+1))+1=0

We multiply parentheses

8x-(2x+2-5(-4x+1))-4+1=0



We calculate terms in parentheses: -(2x+2-5(-4x+1)), so:

2x+2-5(-4x+1)

determiningTheFunctionDomain
2x-5(-4x+1)+2

We multiply parentheses

2x+20x-5+2

We add all the numbers together, and all the variables

22x-3

Back to the equation:

-(22x-3)



We add all the numbers together, and all the variables

8x-(22x-3)-3=0

We get rid of parentheses

8x-22x+3-3=0

We add all the numbers together, and all the variables

-14x=0

x=0/-14

x=0

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