3x+2(5x-4)+10=-7-3(5-2x)-3x

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Solution for 3x+2(5x-4)+10=-7-3(5-2x)-3x equation: 



3x+2(5x-4)+10=-7-3(5-2x)-3x

We move all terms to the left:

3x+2(5x-4)+10-(-7-3(5-2x)-3x)=0

We add all the numbers together, and all the variables

3x+2(5x-4)-(-7-3(-2x+5)-3x)+10=0

We multiply parentheses

3x+10x-(-7-3(-2x+5)-3x)-8+10=0



We calculate terms in parentheses: -(-7-3(-2x+5)-3x), so:

-7-3(-2x+5)-3x

determiningTheFunctionDomain
-3(-2x+5)-3x-7

We add all the numbers together, and all the variables

-3x-3(-2x+5)-7

We multiply parentheses

-3x+6x-15-7

We add all the numbers together, and all the variables

3x-22

Back to the equation:

-(3x-22)



We add all the numbers together, and all the variables

13x-(3x-22)+2=0

We get rid of parentheses

13x-3x+22+2=0

We add all the numbers together, and all the variables

10x+24=0

We move all terms containing x to the left, all other terms to the right

10x=-24

x=-24/10

x=-2+2/5

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