1/3(9k+3)=-2k+16

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Solution for 1/3(9k+3)=-2k+16 equation: 



1/3(9k+3)=-2k+16

We move all terms to the left:

1/3(9k+3)-(-2k+16)=0



Domain of the equation: 3(9k+3)!=0

k∈R



We get rid of parentheses

1/3(9k+3)+2k-16=0

We multiply all the terms by the denominator


2k*3(9k+3)-16*3(9k+3)+1=0

Wy multiply elements

6k^2(9-48k(9+1=0

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