2x-5(x-4)=3+4x-12

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Solution for 2x-5(x-4)=3+4x-12 equation: 



2x-5(x-4)=3+4x-12

We move all terms to the left:

2x-5(x-4)-(3+4x-12)=0

We add all the numbers together, and all the variables

2x-5(x-4)-(4x-9)=0

We multiply parentheses

2x-5x-(4x-9)+20=0

We get rid of parentheses

2x-5x-4x+9+20=0

We add all the numbers together, and all the variables

-7x+29=0

We move all terms containing x to the left, all other terms to the right

-7x=-29

x=-29/-7

x=4+1/7

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