3x+2(2x+2)=13-(2x-5)

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Solution for 3x+2(2x+2)=13-(2x-5) equation: 



3x+2(2x+2)=13-(2x-5)

We move all terms to the left:

3x+2(2x+2)-(13-(2x-5))=0

We multiply parentheses

3x+4x-(13-(2x-5))+4=0



We calculate terms in parentheses: -(13-(2x-5)), so:

13-(2x-5)

determiningTheFunctionDomain
-(2x-5)+13

We get rid of parentheses

-2x+5+13

We add all the numbers together, and all the variables

-2x+18

Back to the equation:

-(-2x+18)



We add all the numbers together, and all the variables

7x-(-2x+18)+4=0

We get rid of parentheses

7x+2x-18+4=0

We add all the numbers together, and all the variables

9x-14=0

We move all terms containing x to the left, all other terms to the right

9x=14

x=14/9

x=1+5/9

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