3-(4w+5)=2(8w+28)

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Solution for 3-(4w+5)=2(8w+28) equation: 



3-(4w+5)=2(8w+28)

We move all terms to the left:

3-(4w+5)-(2(8w+28))=0

We get rid of parentheses

-4w-(2(8w+28))-5+3=0



We calculate terms in parentheses: -(2(8w+28)), so:

2(8w+28)

We multiply parentheses

16w+56

Back to the equation:

-(16w+56)



We add all the numbers together, and all the variables

-4w-(16w+56)-2=0

We get rid of parentheses

-4w-16w-56-2=0

We add all the numbers together, and all the variables

-20w-58=0

We move all terms containing w to the left, all other terms to the right

-20w=58

w=58/-20

w=-2+9/10

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