10+(9-x)+27=10x+(9-x)

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Solution for 10+(9-x)+27=10x+(9-x) equation: 



10+(9-x)+27=10x+(9-x)

We move all terms to the left:

10+(9-x)+27-(10x+(9-x))=0

We add all the numbers together, and all the variables

(-1x+9)-(10x+(-1x+9))+10+27=0

We add all the numbers together, and all the variables

(-1x+9)-(10x+(-1x+9))+37=0

We get rid of parentheses

-1x-(10x+(-1x+9))+9+37=0



We calculate terms in parentheses: -(10x+(-1x+9)), so:

10x+(-1x+9)

We get rid of parentheses

10x-1x+9

We add all the numbers together, and all the variables

9x+9

Back to the equation:

-(9x+9)



We add all the numbers together, and all the variables

-1x-(9x+9)+46=0

We get rid of parentheses

-1x-9x-9+46=0

We add all the numbers together, and all the variables

-10x+37=0

We move all terms containing x to the left, all other terms to the right

-10x=-37

x=-37/-10

x=3+7/10

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