-4(2p+5)8p=-11

Solution for -4(2p+5)8p=-11 equation:

-4(2p+5)8p=-11

We move all terms to the left:

-4(2p+5)8p-(-11)=0

We add all the numbers together, and all the variables

-4(2p+5)8p+11=0

We multiply parentheses

-64p^2-160p+11=0

a = -64; b = -160; c = +11;
Δ = b2-4ac
Δ = -1602-4·(-64)·11
Δ = 28416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28416}=\sqrt{256*111}=\sqrt{256}*\sqrt{111}=16\sqrt{111}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-16\sqrt{111}}{2*-64}=\frac{160-16\sqrt{111}}{-128}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+16\sqrt{111}}{2*-64}=\frac{160+16\sqrt{111}}{-128}
$