3x+16(2x+8)3x-7=(4x-18)2x+25

Solution for 3x+16(2x+8)3x-7=(4x-18)2x+25 equation:

3x+16(2x+8)3x-7=(4x-18)2x+25

We move all terms to the left:

3x+16(2x+8)3x-7-((4x-18)2x+25)=0

We multiply parentheses

96x^2+3x+384x-((4x-18)2x+25)-7=0


We calculate terms in parentheses: -((4x-18)2x+25), so:

(4x-18)2x+25

We multiply parentheses

8x^2-36x+25

Back to the equation:

-(8x^2-36x+25)


We add all the numbers together, and all the variables

96x^2+387x-(8x^2-36x+25)-7=0

We get rid of parentheses

96x^2-8x^2+387x+36x-25-7=0

We add all the numbers together, and all the variables

88x^2+423x-32=0

a = 88; b = 423; c = -32;
Δ = b2-4ac
Δ = 4232-4·88·(-32)
Δ = 190193
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(423)-\sqrt{190193}}{2*88}=\frac{-423-\sqrt{190193}}{176}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(423)+\sqrt{190193}}{2*88}=\frac{-423+\sqrt{190193}}{176}
$