1/4z+17=1

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Solution for 1/4z+17=1 equation: 



1/4z+17=1

We move all terms to the left:

1/4z+17-(1)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

1/4z+16=0

We multiply all the terms by the denominator


16*4z+1=0

Wy multiply elements

64z+1=0

We move all terms containing z to the left, all other terms to the right

64z=-1

z=-1/64

z=-1/64

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