3x+14-5(x-3)=4(x+3-7)

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Solution for 3x+14-5(x-3)=4(x+3-7) equation: 



3x+14-5(x-3)=4(x+3-7)

We move all terms to the left:

3x+14-5(x-3)-(4(x+3-7))=0

We add all the numbers together, and all the variables

3x-5(x-3)-(4(x-4))+14=0

We multiply parentheses

3x-5x-(4(x-4))+15+14=0



We calculate terms in parentheses: -(4(x-4)), so:

4(x-4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

-2x-(4x-16)+29=0

We get rid of parentheses

-2x-4x+16+29=0

We add all the numbers together, and all the variables

-6x+45=0

We move all terms containing x to the left, all other terms to the right

-6x=-45

x=-45/-6

x=7+1/2

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